Question

Temp(K) 350 400 k(rate constant, min-1 0.0390 0.0474 Kc(equlibrium constant) 3.9530 1.6187 R = 2cal /...

Temp(K) 350 400
k(rate constant, min-1 0.0390 0.0474
Kc(equlibrium constant) 3.9530 1.6187

R = 2cal / K mol

1)activation energy

2)reaction heat

3)Equilibrium conversion rate

please..

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