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If air at 65 degrees Fahrenheit and 50% humidity enters a furnace which heats the air...

If air at 65 degrees Fahrenheit and 50% humidity enters a furnace which heats the air to 120 degrees Fahrenheit. What is the relative humidity of the air leaving the furnace.
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Answer #1

using the August-Roche-Magnus approximation.

TD: =243.04*(LN(RH/100)+((17.625*T)/(243.04+T)))/(17.625-LN(RH/100)-((17.625*T)/(243.04+T)))

RH: =100*(EXP((17.625*TD)/(243.04+TD))/EXP((17.625*T)/(243.04+T)))

Where, RH = Relative Humidity

T = temperature

Td= Dew point temperature

AT T=120F and RH=50%

Calculating

TD: =243.04*(LN(RH/100)+((17.625*T)/(243.04+T)))/(17.625-LN(RH/100)-((17.625*T)/(243.04+T)))

TD= 45.91F

And now putting TD=45.91F and T=120F, for calculating RH

RH: =100*(EXP((17.625*TD)/(243.04+TD))/EXP((17.625*T)/(243.04+T)))

RH= 9% Answer

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