Question

A Newtonian liquid food with a viscosity of 2.5 cP and a density of 1020 kg/m3...

A Newtonian liquid food with a viscosity of 2.5 cP and a density of 1020 kg/m3 is to be pasteurized in a HTST system that heats the liquid food to 80°C followed by holding it in a 0.02 m diameter pipe for a minimum time of 0.07 min.

a. Calculate maximum velocity and the length of the holding tube required, given that the flow rate is 35 L/min.

b. The temperature at the cold spot for a liquid food in a can is as follows (Table Q2). The sterilization process is being applied to a microbial population with D121 of 1.1 min and z = 11°C. Calculate the total lethality for the sterilization process.

Time (min) 0 1 2 3 4 5 6

Temperature (°C) 80 105 130 135 125 115 105

Homework Answers

Answer #1

Flow Rate = Area of Pipe* Velocity of Fluid

Hence the maximum velocity achievable in a pipe= 2*v = 2*1.8568 = 3.7136 m/s

And the length of the pipe then shall be 2*8 = 16 m

Lethality :

Time(min) Δt T(^0C) Lethality (L) F0(min)
0 0 80 0.0001835 0
1 1 105 0.034384573 0.034384573
2 1 130 6.44304121 6.44304121
3 1 135 18.35001247 18.35001247
4 1 125 2.262275304 2.262275304
5 1 115 0.278903873 0.278903873
6 1 105 0.034384573 0.034384573
Sum = 27.403003

Total F0 = 27.403003 minutes

Hence Lethality :

Please comment for any doubts :)

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