A student prepares a sample of hydrogen gas by electrolyzing water at 25°C. She collects 112 mL of H2 at a total pressure of 758 mm Hg. Vapor pressure of water at 25°C = 23.76 mm Hg, calculate:
Solution :
total pressure of 758 mm Hg l, PH2 = 758 mm Hg
Vapor pressure of water at 25°C = 23.76 mm Hg
PH2O = 23.76 mm Hg
Total peessure = PH2 = Patm - PH2O
PH2 =758 mm Hg – 23.76 mm Hg
PH2 = 734.24 mm Hg = 0.966 atm
the partial pressure of hydrogen is 734.24 mm Hg
Volume of H2 = 112 ml = 0.112 L
Temperature = 25 c = 298 K
PV = nRT
(0.966 atm)(0.112 L) = (n)(0.0821 L·atm/mol·K)(298 K)
n = 0.00442 mol H2
the number of moles of hydrogen collected is 0.00442 mol H2
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