Calculate the standard enthalpy of formation of Ga2H6(g) (in kJ/mol) from the following data:
2 Ga(s) + 3/2 O2(g)-->Ga2O3(s). ΔHo = –1188
kJ/mol
Ga2H6(g) + 3 O2(g)-->Ga2O3(s) + 3 H2O(l). ΔHo = –2158 kJ/mol
H2(g) + 1/2 O2(g)--> H2O(g) ΔHo = –242 kJ/mol
H2O(l)-->H2O(g) ΔHo = +44 kJ/mol
2 Ga(s) + 3 H2(g)-->Ga2H6(g). ΔHo = ? kJ/mol
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