Question

1_Find the required amount of ZnSO4 to prepare 0.3 M 450 mL ZnSO4 solution. (MWZnSO4= 161.47...

1_Find the required amount of ZnSO4 to prepare 0.3 M 450 mL ZnSO4 solution. (MWZnSO4= 161.47 g/mole)

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of...
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of a 1 M NaOH solution. 2). The mass of potassium hydrogen phthalate (KHP) required to react with 25 mL of a 1 M NaOH solution. The molecular weight of KHP is 204.23 g/mol. 3). The amount of water required to dissolve the quantity of KHP calculated in (b), given that the solubility of KHP is 10.2 grams per liter.
What mass of nano3 must be added to 450. g of water to prepare a solution...
What mass of nano3 must be added to 450. g of water to prepare a solution that is 0.0494 m in NaNO3? What is the mole fraction of nano3 in the solution?
28.7 mL of KOH solution required 21.3 mL of 0.118 M HCl for neutralization. What mass...
28.7 mL of KOH solution required 21.3 mL of 0.118 M HCl for neutralization. What mass (g) of KOH was in the original sample? (MW KOH = 56 g/mole) Express your answer using 3 significant figures
Calculate the amount 0.5 M EDTA solution (MW= 292.24 g/mol) required to make 400 mL of...
Calculate the amount 0.5 M EDTA solution (MW= 292.24 g/mol) required to make 400 mL of 70.0 mM solution?
Calculate the volume (mL) of 1.0 M metal nitrate solution required to prepare 3.0 g of...
Calculate the volume (mL) of 1.0 M metal nitrate solution required to prepare 3.0 g of CaCO3. Again, using the balanced chemical equation you should be able to relate the moles of pigment to the moles of metal nitrate and from that calculate the volume of 1.0 M metal nitrate solution required. Balanced equation: Ca(NO3)2 (aq) + K2CO3 (aq) ↔ CaCO3 (s) + 2KNO3 (aq)
A) How many mL of 12.25 M NaOH are required to prepare 525.00 mL of 0.800...
A) How many mL of 12.25 M NaOH are required to prepare 525.00 mL of 0.800 M NaOH solution in DI water? B) How much DI water is required?
what mass of solid calcium nitrate, in grams, should be measured out to prepare 450. ml...
what mass of solid calcium nitrate, in grams, should be measured out to prepare 450. ml of a .100 M solution
A buffer is formed by mixing 450 mL of a 0.388 M sodium formate solution with...
A buffer is formed by mixing 450 mL of a 0.388 M sodium formate solution with 375 mL of a 0.450 M formic acid, HCHO2, solution. What is the pH of the new solution? Correct Answer: 3.78 -I just want to know the process for the problem. Thanks!
Need to figure out how to do these. (1a) Prepare 100.0 mL of 0.1250 M copper(II)acetate...
Need to figure out how to do these. (1a) Prepare 100.0 mL of 0.1250 M copper(II)acetate solution from solid cupric acetate monohydrate. The molar mass of Cu(CH3COO)2•H2O is 199.64 g/mole. (b) Prepare 25.00 mL of 0.05000 M copper(II)acetate solution from your 0.1250 M solution. (2a) Prepare 100.0 mL of 0.001000 M KMnO4 solution from the 0.02000 M KMnO4. (b) Prepare 25.00 mL of 4.000x10-4 M KMnO4 solution from your 0.001000 M KMnO4 solution. (3a)10.00 mL of 8.75x10-4 M CrO4-2 solution...
If   14.99 mL of NaOH are required to titrate 15.00 mL of a   0.46 M oxalic acid solution,...
If   14.99 mL of NaOH are required to titrate 15.00 mL of a   0.46 M oxalic acid solution, what is the concentration of the NaOH? A solution of a theoretical triprotic acid was prepared by dissolving 4.980 g of solid in enough DI water to make 500.0 mL of solution.   10.10 mL of a 0.448 M solution was required to titrate 20.00 mL of this acid's solution. 1. What is the concentration of the acid solution? 2. What is the molar mass...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT