Question

9). 99mTc eluate yielded 2.0 Ci at 6:30 am in a 20ml vial.       a. What is...

9). 99mTc eluate yielded 2.0 Ci at 6:30 am in a 20ml vial.

      a. What is the concentration at 6:30pm? (Please use mCi)


b. What is the concentration at 10:00pm?


explain your answer

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Homework Answers

Answer #1

Solution:

Half life of 99mTc, t1/2 = 6 hours

Decay constant,

Initial activity, Ao = 0.5 Ci

Time between 6:30 am to 6:30 pm, t = 12 hr

Therefore, the activity after 12 hr

A = 0.125 Ci

Therefore, the concentration at 6:30 pm is

= (0.125 Ci)/20ml

= 0.00625 Ci/ml

= 6.25 mCi/ml

Part (b):

Total time from 6:30 am to 10:00 pm, t = 15.5 hr

Therefore, the activity after 12 hr

A = 0.083427 Ci

Therefore, the concentration at 6:30 pm is

= (0.083427 Ci)/20ml

= 0.0041714 Ci/ml

= 4.1714 mCi/ml

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