Question

**9). 99mTc eluate yielded 2.0 Ci at 6:30 am in a 20ml
vial.**

** a. What is the
concentration at 6:30pm? (Please use mCi)**

**b. What is the concentration at 10:00pm?**

explain your answer

Answer #1

*Solution:*

Half life of 99mTc, t1/2 = 6 hours

Decay constant,

Initial activity, Ao = 0.5 Ci

Time between 6:30 am to 6:30 pm, t = 12 hr

Therefore, the activity after 12 hr

A = 0.125 Ci

Therefore, the concentration at 6:30 pm is

= (0.125 Ci)/20ml

**= 0.00625 Ci/ml**

**= 6.25 mCi/ml**

**Part (b):**

Total time from 6:30 am to 10:00 pm, t = 15.5 hr

Therefore, the activity after 12 hr

A = 0.083427 Ci

Therefore, the concentration at 6:30 pm is

= (0.083427 Ci)/20ml

**= 0.0041714 Ci/ml**

**= 4.1714 mCi/ml**

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