Question

using interpolation calculate the enthalpy of saturated liquid R-134a at P= 680 kPa a 558 kJ/kg...

using interpolation calculate the enthalpy of saturated liquid R-134a at P= 680 kPa

a 558 kJ/kg
b 88 kJ/kg
c 350 kJ/kg
d 120 kJ/kg
Engineering   Chemical-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Here is the solution for your question I hope I could help you in future also if anything is not clear to you please let me know before giving your valuable feedback I would like to improve that in the future .

Thanks

Solution

I hope it will help you if I missed anything or anything is not clear to you please let me know before giving your rating.

Thanks

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An ice-making machine operates on the ideal vapor-compression cycle, using R-134a. The refrigerant enters the compressor...
An ice-making machine operates on the ideal vapor-compression cycle, using R-134a. The refrigerant enters the compressor as saturated vapor at 140 kPa and leaves the condenser as saturated liquid at 600 kPa. Water enters the ice machine at 13oC and leaves as ice at -4oC, while removing heat at 393 kJ per kg of water. Estimate the mass flow rate of the refrigerant and the power input to the ice machine for an ice production rate of 7 kg/h.
1 kg of water in a piston cylinder arrangement is initially in a saturated liquid state...
1 kg of water in a piston cylinder arrangement is initially in a saturated liquid state at 1 bar. It undergoes expansion at constant pressure due to external heat supply to it, to a final state of saturated vapor. (i) What is the initial temperature of water in C? (a) 93.50 (b) 96.71 (c) 99.63 (d) 111.4 (e) 12.2 (ii) What is the change in enthalpy of water (kJ/kg-K)? (a) 417.46 (b) 2258.0 (c) 2675.5 (d) 2506.1 (iii) What is...
500 kg of saturated liquid at 11 MPA is heated at constant pressure until it reaches...
500 kg of saturated liquid at 11 MPA is heated at constant pressure until it reaches a temperature of 450 C find the following: a. enthalpy entropy and specific volume at the end of the process b. change in entropy in kj/kg k of the process c. amount of heat needed for the process
Using thermodynamic tables, and interpolation where needed, at p = 3 bar, v = 0.5 m3/kg,...
Using thermodynamic tables, and interpolation where needed, at p = 3 bar, v = 0.5 m3/kg, compute T in °C and u in kJ/kg. Also locate the state on sketches of the p–v and T–v diagrams.
Initially (state 1) a well-insulated rigid tank contains 20 kg of a saturated liquid-vapor mixture of...
Initially (state 1) a well-insulated rigid tank contains 20 kg of a saturated liquid-vapor mixture of water at 100 kPa and half of the mass is in the liquid phase. An electric resistance heater placed in the tank is now turned on and kept on until all the liquid in the tank is vaporized (state 2). Determine (a) the initial specific volume in m3/kg, (b) the final specific entropy in kJ/kg.K and (c) change of entropy in kJ/K.
Initially (state 1) a well-insulated rigid tank contains 20 kg of a saturated liquid-vapor mixture of...
Initially (state 1) a well-insulated rigid tank contains 20 kg of a saturated liquid-vapor mixture of water at 100 kPa and half of the mass is in the liquid phase. An electric resistance heater placed in the tank is now turned on and kept on until all the liquid in the tank is vaporized (state 2). Determine (a) the initial specific volume in m3/kg, (b) the final specific entropy in kJ/kg.K and (c) change of entropy in kJ/K.
Ammonia is brought from saturated vapor at 300 kPa to 1400 kPa, 140oC in a steady...
Ammonia is brought from saturated vapor at 300 kPa to 1400 kPa, 140oC in a steady flow adiabatic compressor. Thermodynamic properties of ammonia at initial and final states are given as : h1= hi = 1431.7 kJ/kg, s1 = s­i = 5.4565 kJ/kg-K h2= he = 1752.8 kJ/kg, s2= se = 5.7023 kJ/kg-K          h2,s = he,s = 1656.08 kJ/kg a) Find the actual specific work input to the compressor. b) Calculate the specific work input to the compressor for isentropic...
0.75 kg of refrigerant-134a at 120 kPa and 20°C initially fills a piston-cylinder device. Heat is...
0.75 kg of refrigerant-134a at 120 kPa and 20°C initially fills a piston-cylinder device. Heat is now transferred to the refrigerant from a source at 150°C, and the piston which is resting on a set of stops, starts moving when the pressure inside reaches 140 kPa. Heat transfer continues until the temperature reaches 90°C. Assuming the surrounding to be at 25°C and 100 kPa, determine (a) the work done, (b) the heat transfer, (c) the exergy destroyed, and (d) the...
0.75 kg of refrigerant-134a at 120 kPa and 20°C initially fills a piston-cylinder device. Heat is...
0.75 kg of refrigerant-134a at 120 kPa and 20°C initially fills a piston-cylinder device. Heat is now transferred to the refrigerant from a source at 150°C, and the piston which is resting on a set of stops, starts moving when the pressure inside reaches 140 kPa. Heat transfer continues until the temperature reaches 90°C. Assuming the surrounding to be at 25°C and 100 kPa, determine (a) the work done, (b) the heat transfer, (c) the exergy destroyed, and (d) the...
A piston-cylinder contains 2 kg of refrigerant R-134a at temperature -20 degrees Celsius and a quality...
A piston-cylinder contains 2 kg of refrigerant R-134a at temperature -20 degrees Celsius and a quality of 20% is heated in device until it reaches a saturated mixture with quality 60%. a) Show process on a P-v and P-T diagram b) What is the pressure? c) What is the change in volume? d) What is the change in the internal energy? e) Redo the problem if the piston-cylinder assembly is replaced with a rigid container.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT