Question

A 430. mL solution of 0.230 M HBr(aq) is mixed with a solution of 225 mL of 0.350 M HClO4(aq). How many moles of H+(aq) are present in the final solution?

Answer 1

GIVEN DATA:

volume of HBr = 430 ml = 0.430 L

Concentration of HBr = 0.230 M

Concentration of HClO4 = 225 ml = 0.225 L

Molarity of HClO4 = 0.350 M

So,

Concentration of H+ from HBr = 0.230 M

Concentration of H+ from HClO4 = 0.350 M

Now:

moles of H+ from HBr = 0.430 L * 0.230 moles/L = 0.0989 moles

moles of H+ from HClO4 = 0.225 L * 0.350 moles/L = 0.0788 moles

So total moles of H+ = 0.0989 + 0.0788 = 0.1777 moles

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