A processes that generates NO burns NH3 with oxygen fed with 20% excess
NH3 +O2 à NO +H2O
The reaction consumes 70% of the NH3. The NO is separated from the NH3 which didn’t react and is then recirculated to the feed.
a) Draw the flow diagram
b) Balance the chemical reaction
c) Find the moles of NO formed per 100 moles of NH3 fed.
d) Find the ratio of recirculated NH3 per formed mole of NO.
a)
As per the data provided
b)
Now the reaction given in the question
NH3 + O2 ------>NO +H20
Now we will balance the above reaction.
We will simply do the atomic species balance ( The number of atoms in LHS should match RHS)
NH3 + 2O2 ------>NO +(3/2)*H20
C) mols of 100 mols of NH3
Conversion of NH3 is 70 %
From reaction stoichiometry
1 nol NH3 = 1 mol NO
Mols of NH3 reacted = 0.7*100 = 70 mols
Mols of NO produced = 70 mols
d)
Mols of NH3 reacted = (1-0.7)*100 = 30 mols
As per the data provided in question, unreacted ammonia is reacted back
Hence, Ammonia recycled = 30 mol
mols of NO produced = 70 mols
Ratio of NH3 to NO produced = 30/70 =0.4286
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