Say you are given a process with 3 different sequential tasks, with average times as follows task 1 = 3.0 min, task 2= 2.5 min, and task 3= 1.2 min. Given Tr=0, and 400 units must be produced in a 10 hour shift answer the following:
a) What is the line balance (min/unit) Tc = Ts?
b) What is the balance efficiency (%) of the line?
please show math
a) Line balancing is done by identifying and adding the minimum number of resources required to meet the desired production rate
In this case, the total duration of tasks = 3+2.5+1.2 =6.7 min
the cycle time to meet 400 units in 10 hour = 10*60/400 = 1.5 min
Additional resource required = 6.7/1.5 =4.47 = 5 Resources
Refer the attached image for task wise work out of line balancing
Now that we know how many resources are required, we can calculate the balance efficiency
Balance Efficiency = Total work content time / Total Available time.
in the above work out,
Total Work content time = 400 *6.7 = 2680 min
Total Available time = 5*10*60 = 3000 min ( 5 resources working at 10 hrs per shift)
Balance Efficiency = 2680/3000 = 0.89
Refer the attached image for task wise work out of Balance Efficiency
Get Answers For Free
Most questions answered within 1 hours.