Question

A methods and measurements analyst for Timepiece, Inc., needs to develop a time standard for the task of attaching a watch to a wristband. In a preliminary study, he observed one of his workers perform this task five times, with the following results:

Observation	1	2	3	4	5
Time (secs)	29	23	31	37	26

What is the standard time for this task if the employee worked at a 9 percent slower pace than average, and an allowance of 23 percent of the workday is used?

(Keep two decimal places in your answer)

Answer 1

Average observed time = ( 29 + 23 + 31 + 37 + 26) / 5 = 29.2 secs

Performance rating factor = 91 % ( since it is mentioned that workers work at a 9 percent slower place )

Therefore ,

Normal time = Performance rating factor (%) / 100 x Average observed time = 0.91 x 29.2 = 26.57 seconds

Given,

Allowance factor = 23 percent

Therefore , Standard time = ( 1 + allowance factor/100) x Normal time = 1.23 x 26.57 seconds = 32.68 seconds

STANDARD TIME FOR THIS TASK = 32.68 SECONDS