Needless Markup (NM), a famous “high end” department store, must decide on the quantity of a high-priced woman’s handbag to procure in Spain for the coming Christmas season. The unit cost of the handbag to the store is $28.50 and the handbag will sell for $150.00. Any handbags not sold by the end of the season are purchased by a liquidator for $10.00 each. In addition, the store accountants estimate that there is a cost of $0.40 for each dollar tied up in inventory, as this dollar invested elsewhere could have yielded a gross profit. Assume that this cost is attached to unsold bags only. Due to the long distance and limited capacity, NM must place the order 6 months in advance. A detailed analysis of past data shows that if forecasting 6 months in advance, the number of bags sold can be described by a normal distribution, with mean 150 and standard deviation 60.
a) Another supplier in the U.S. offers the same product but at a higher price of $35 due to its higher production cost. For this supplier, NM only needs to place the order 3 months in advance which results in a much better forecast. Past data shows if ordering 3 months in advance, the number of bags sold can be described by a normal distribution, with mean 150 and standard deviation 20. Which supplier should NM choose?
Option 1: Spain
6 month duration demand analysis:
m | mean | 150 | |
s | Std Dev | 60 | |
C | Cost | 28.5 | |
P | Price | 150 | |
V | Salvage | 10.4 | (10+0.4) |
Formula used | |||
Cu | Cost of under order | 121.5 | (P-C) |
Co | Cost of over order | 18.1 | (C-V) |
CR | Critical ratio | 0.8703 | (Cu/(Cu+Co) |
So actual order | m+Z*s | ||
218 | NORMINV(CR,m,s) | ||
If | Optimal Order is | 218 |
So profit is 218*121.5 =
26448 |
For option 2: US
For 3 months demand analysis::
m | mean | 150 | |
s | Std Dev | 60 | |
C | Cost | 35 | |
P | Price | 150 | |
V | Salvage | 10.4 | (10+0.4) |
Formula used | |||
Cu | Cost of under order | 115 | (P-C) |
Co | Cost of over order | 24.6 | (C-V) |
CR | Critical ratio | 0.8238 | (Cu/(Cu+Co) |
So actual order | m+Z*s | ||
206 | NORMINV(CR,m,s) | ||
If | Optimal Order is | 206 |
SO profit: 206*115=
23666 |
So in 6 months = 2*23666 =
47332.28 |
Hence option 2 is better.
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