Question

A company has a production line for the manufacture of an item. The line is composed of 8 work stations which have the following information. The line is designed with an allowable standard time of 0.58 minutes per piece in each of them. The lower table gives the standard times applied in the production line.

A.Time of the first piece produced
B.cycle time
C.efficiency of the line
D. Profuction per shift (8 hours considering 10% of lost time)
E.number of operators per station to produce 1000 pieces per day and maintain the same efficiency.
F) total number of workers in the production area .

Station	Standard time applied to the operation (min/piece)	Operators per station (subsection E)
1	0.40
2	0.49
3	0.50
4	0.51
5	0.58
6	0.50
7	0.38
8	0.48

Answer 1

A) Time of the first piece produced = .4+.49+.5+.51+.58+.5+.38+.48 = 3.84 min

B) Cycle time = 0.58 min

C) Lead time = Cycle time * Number of stations = 0.58*8 = 4.64 min

Efficiency of the line = Sum of task times / Lead time

= 3.84/4.64

= 0.8276 or 82.76 %

D) Production per shift = 8*60*(1-10%)/0.58 = 744.8

E) Demand rate = 1000 pcs per day

Available time per day = 8*60*(1-10%) = 432 minutes

Takt time = Available time per day / Demand rate = 432/1000 = 0.432 minutes

Operators required on each station = Standard time / Takt time . If this comes to fraction, then it is rounded up

FORMULAS:

C2 =ROUNDUP(B2/0.432,0) copy to C2:C9

F) Total number of operators required

= 1+2+2+2+2+2+1+2

= 14 operators