Question 2 [13 Marks]
Activity |
Original Duration (in Months) |
Crash Duration (in Months) |
Time Savings |
Original Cost in Dollars |
Crash Cost |
Extra Cost |
Cost per Month |
F |
14 |
12 |
2 |
10,000 |
14,000 |
4,000 |
2,000 |
A |
9 |
8 |
1 |
17,000 |
27,000 |
10,000 |
10,000 |
H |
3 |
2 |
1 |
25,000 |
26,000 |
1,000 |
1,000 |
G |
7 |
5 |
2 |
10,000 |
16,000 |
6,000 |
3,000 |
C |
11 |
8 |
3 |
27,000 |
36,000 |
9,000 |
3,000 |
Crash H is by 1 month
Crash F is by 2 months
GIven the float is -3, the project has to be crashed by 3 months to bring it back on track.
Therefore , first crash H by 1 month since it has the least extra cost per month of $1,000.
The maximum time saving for H was 1 month.
So, next move on to the activity F for it has the next least extra cost per month of $2,000.
Crash F by 2 months which was the maximum time-saving.
Total cost of crashing = 1 month of H * $1,000/ month + 2 months of F * $2,000/ month = $5,000
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