Question:
The time to make beds at a motel should fall into an agreed-on range of times. A sample of four maids was selected, and the time needed to make a bed was observed on three different occasions:
Maid | Sample 1 (sec) | Sample 2 (sec) | Sample 3 (sec) |
---|---|---|---|
Ann | 120 | 90 | 150 |
Linda | 130 | 110 | 140 |
Marie | 200 | 180 | 175 |
Michael | 165 | 155 | 140 |
a. Determine the upper and lower control limits for an X-bar chart and R-chart with a sample size of four.
b. After the control chart was established a sample of four observations has the following times in seconds: 180, 198, 193, and 218. Is corrective action needed?
Given
Sample size =4
Maid | Sample1(Sec) | Sample2(sec) | Sample3(Sec) | Mean=sum of 3 samples/3 | Range=(Max-Min) |
Ann | 120 | 90 | 150 | 120.00 | 60 |
Linda | 130 | 110 | 140 | 126.67 | 30 |
Marie | 200 | 180 | 175 | 185.00 | 25 |
Michael | 165 | 155 | 140 | 153.33 | 25 |
585.00 | 140.00 | ||||
Xbar = Sum of means/4= | 146.25 | ||||
Rbar= Sum of Ranges/4 = | 35 |
Xbar = 146.25
Rbar=35
A2 = 0.729 , D3 =0 ,D4=2.282 ( For sample size 4)
(a)
For X-bar chart
UCL = Xbar + A2* Rbar = 146.25+0.729*35 =146.25 + 25.51 =171.76
LCL = Xbar - A2* Rbar = 146.25 - 0.729*35 =146.25 - 25.51 =120.74
For R-bar chart
UCL=D4*Rbar =2.282*35 =79.87
LCL =D3*Rbar = 0*35 =0
(b)
Observations are 180,198,193, 218.
All the readings are above the upper control limit , hence corrective action is needed.
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