Question

A production manager at a Contour Manufacturing plant has inspected the number of defective plastic molds...

A production manager at a Contour Manufacturing plant has inspected the number of defective plastic molds in five random samples of 35 observations each. Following are the number of defective molds found in each sample:

Construct a 3-sigma control chart (z = 3) with this information. (If the lower control limit is negative, round the LCL to zero and all other answers to 2 decimal places, e.g. 15.25.)

CL:

UCL:

LCL:

Sample Number of
Defects		 Number of
Observations
in Sample
1 0 35
2 1 35
3 2 35
4 1 35
5 2 35
Total 6 175
Business   Operations-Management   
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Answer #1

To solve this given problem, we'll first find the mean and standard deviation of the five samples through MS Excel functions Average and STDEV respectively

The mean of the given data = 1.20

The Standard deviation of the given data = 0.84

Sample size = n = 35

Since the required sigma level = 3

UCL = Mean + [3 x (SD / Sqrt(n)] = 1.20 + [3 x (0.84 / sqrt(35)]

= 1.20 + [3 x 0.14] = 1.62

LCL = Mean - [3 x (SD / Sqrt(n)] = 1.20 - [3 x (0.84 / sqrt(35)]

= 1.20 - [3 x 0.14] = 0.78

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