A project activity has an optimistic time estimate of three days, a most likely time estimate of eight days, and a pessimistic time estimate of 10 days. The expected time (in days) of this activity is:
7 |
||
7.5 |
||
8 |
||
8.5 |
||
10 |
Answer: 7.5
Explanation:
Given optimistic time estimate, o = 3 days
Most likely time estimate, m = 8 days
Pessimistic time estimate, p = 10 days
Expected time for the activity, T_{e} = [o + 4m + p]/6
= [3+ (4 x 8) + 10] / 6 = 7.5 days
Hence the answer is second option, 7.5
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