Source of Variation |
Sum of Squares |
Degrees of Freedom |
Mean Square |
F |
Between Treatments |
126 |
_____? |
_____? |
_____? |
Within Treatments |
240 |
_____? |
_____? |
|
(Error) |
||||
Total |
_____? |
67 |
Use α = 0.05 to determine if there is any significant difference among the means of the eight groups.
Solution:-
Source of Variation |
Sum of Squares |
Degrees of Freedom |
Mean Square |
F |
Between Treatments |
126 |
7 |
18 |
4.5 |
Within Treatments (Error) |
240 |
60 |
4 |
|
Total |
366 |
67 |
1) Total sum of square = Sum of treatment square + sum of error square
= 126 + 240 = 366
2) Degree of freedom
Degree of freedom treatment (DFT) = 8-1= 7
Degree of freedom error = Total DF - DFT = 67-7 = 60
3) Mean square
Mean square treatment (MST) = Treatment sum of square/Treatment degree of freedom
= 126/7 = 18
Mean square error (MSE) = error sum of square/error degree of freedom
= 240/60= 4
4) The F- test
F = MST/MSE = 18/4 = 4.5
Critical value of F at = 0.05 = 2.17
Since
So, H0 is rejected.
Therefore there is a significant difference among the means of the eight group
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