Demand |
100 units per week |
Standard deviation of weekly demand |
10 units |
Average lead time |
10 days |
Standard deviation of the lead time |
5 days |
Cycle service level |
70 % |
Considering a continuous review system,
demand per week | 100.00 | ||
Lead time, LT | 10.0 | ||
Order quantity, Q= | √(2*S*D/H) | 141 | |
standard deviation of weekly demand, Sd | 10.0 | ||
standard deviation of lead time, SLT | 5.00 | ||
Answer a. | Standard deviation of lead time demand, SdLT | SQRT((LT*(Sd)^2) + (d*SLT)^2)) | 501.00 |
Service level desired | 70.0% | ||
Z value at service level, z | NORMSINV(service probability) | 0.52 | |
Answer b | Safety stock, SS | z*SdLT | 263 |
Lead Time Demand | ( LT * daily Demand) | 1000 | |
Answer c | Reorder point | Lead time demand+Safety stock | 1263 |
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