Question

The estimated time for the critical path is 44.5 weeks.

?The activity variance along the critical path is 22.027 weeks.

?f) The probability that Hopkins Hospitality will finish the project in 40 weeks or less is ?

?(Enter as a probability and round your response to three decimal? places.)

Answer 1

The estimated time for the critical path = m = 44.5 weeks

Variance of the critical path = 22.027 weeks

Therefore, standard deviation of the critical path = Sd = Square root ( 22.027 ) = 4.693 weeks

Let Z value for the probability that the project will finish in 40 weeks or less = Z1

M + Z1 x sd = 44

Or, 44.5+ 4.693.Z1 = 40

Or, 4.693.Z1 = - 4.5

Or, Z1 = - 0.9588 ( - 0.96 rounded to 2 decimal places )

Corresponding probability for Z = - 0.96 as derived from standard normal distribution table is 0.16853 ( 0.168 rounded to 3 decimal places )

PROBABILITY THAT THE HOPKINS HOSPITAL WILL FINISH THE PROJECT 40 WEEKS OR LESS = 0.168