Customers arrive at a suburban ticket outlet at the rate of 3 per hour on Monday mornings. This can be described by a Poisson distribution. Selling the tickets and providing general information takes an average of 10 minutes per customer, and varies exponentially. There are 3 ticket agents on duty on Mondays. On Average, how much time does a customer spend Waiting in Line?
Question 5 options:
.001 

.167 

.0005 

.1837 

None of the Answers Listed is Correct 
Arrival rate (A or lambda) = 3 per hour
Service rate (S or mu) = 10 minutes per customer or 60/10 customers per hour = 6 per hour
M (Number of agents) = 3
Number of customers in line = Lq
Lq for A/S = 3/6 = 0.5 and M = 3 as per below table is 0.003
Waiting time in line = Lq/A = 0.003/3 = 0.001 hours
Ans 0.001
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