A medical facility was designed for 500 lab tests per day. Since this facility has been converted to do tests only for coronavirus, its effective capacity has been reduced to 450 tests per day. Its actual output based on the past 7 day’s data is 300 tests per day.
a. Calculate the efficiency and utilization of this facility.
b. What does this facility have to do to operate at 80% efficiency?
c. What do you think might be some factors that are contributing to a lower effective capacity?
Answer (a): Designed capacity = 500 tests
Effective Capacity = 450 tests
Actual capacity = 300 tests
Facility Efficiency = (300/450) × 100 = 66.67 %
Facility Efficiency = 66.67%
Facility Utilisation = (300/500) × 100 = 60%
Facility Utilisation = 60%
Answer (b): To increase the efficiency of the Facility from 66.67% to 80% , the facility must increase its actual output.
Let's assume X tests are needed to be done ler day to achieve the efficiency of 80%.
Facility Efficiency = ( output/ Effective Capacity) × 100
Facility Efficiency = (X/450) × 100 = 80
100 X = 450 × 80
X = 36000/100
X = 360
It means to gain Facility efficiency of 80% , facility must increase its actual output to 360 Per day.
Efficiency in this case can be increased by providing proper training and experience to the Employees because Employees have no experience and little training in lab tests relating to Coronavirus, so to increase efficiency, Employees must be trained well.
Answer (c): Factors Contributing to Lower Effective Capacity
Effective Capacity is the output that can be produced at maximum given the various constraints such as Human Resource constraint or process constraint. Some factors that contribute to lower effective Capacity in this facility are:
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