Jon Doe, owner of a local donut shop, recorded it's production quantities, demands, and actual sales of the past 5 days. Assume that any leftover odnuts by the end of the day is discarded and that any excess demand that cannot be satisfied immediately is lost.
Day | Production Quantity | Demand | Actual Sales |
1 | 90 | 120 | 90 |
2 | 75 | 100 | 75 |
3 | 100 | 90 | 90 |
4 | 100 | 80 | 80 |
5 | 80 | 160 | 80 |
i) Calculate the Type-I customer service level (Cycle Service Level) for the last 5 days.
ii) Calculate the Type-II customer service level (Fill rate) for the last 5 days
At Type I customer service level ( Cycle service level ) , one needs to determine proportion of time a customer’s demand is met. As per data provided in last 5 days , it was only on day 3 and day 4 the full demand was met. On other 3 days ( i.e. on day 1 , day 2 and day 5 ) only part of the demand were catered by low level of sales.
Therefore customer service level is 2 out of 5 cases = 2/ 5 = 0.40 ( or 40 %)
At Type II customer service level ( fill Rate ) , one calculates proportion of total demand quantity which have been mate.
Total demand in last 5 days = 120 + 100 + 90 + 80 + 160 = 550
Total sales in last 5 days = 90 + 75 + 90 + 80 + 80 = 415
Therefore fill rate = Total sales/ Total demand x 100 = 415/550 x 100 = 0.7545 ( 75,45%)
TYPE I CUSTOMER SERVICE LEVEL = 40% |
TYPE II CUSTOMER SERVICE LEVEL = 75.45% |
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