Providence Assessment Center screens and trains employees for a
computer assembly firm in Boston. The progress of all trainees is
tracked and those not showing the proper progress are moved to less
demanding programs. By the tenth repetition trainees must be able
to complete the assembly task in 1 hour or less. Susan Sweaney has
just spent 6 hours on the fourth unit and 4 hours completing her
eighth ?unit, while another? trainee, Julie? Burgmeier, took 4
hours on the third and 3 hours on the sixth unit.
Time required by Susan for the tenth ?unit: ?(Note: You must round
all intermediate calculations to at least three decimal places
before proceeding with subsequent? calculations.)
10th unit ____hours (round your response to two decimal? places).
We have to first determine Learning rate for both persons.
Learning Rate can be described in terms of percentage and fraction.
Thus , when the quantity doubles , the time taken to perform the doubled unit becomes Learning rate( %) /100 x Initial unit
‘Thus , if Susan has spent 6 hours on the 4th unit and 4hours for the 8th unit , Learning rate = 4/6 x 100 = 66.67%
Similarly, if Julie took 4 hours on the third and 3 hours on the sixth unit , Learning rate = 3/ 4 x 100 = 75 %
We will use Standard learning curve table and Learning rate of 66.67% of Susan to derive:
Accordingly,
Time required by Susan for the first unit = 13.5 hours
Time required for the 10th unit = 3.51 hours
10th UNIT = 3.51 HOURS |
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