Ross Hopkins, president of Hopkins Hospitality, has developed the tasks, durations, and predecessor relationships in the following table for building new motels.
Time
(weeks ) |
Immediate |
Time
(weeks ) |
Immediate |
||||||||||||
Activity |
a |
m |
b |
Predecessor(s) |
Activity |
a |
m |
b |
Predecessor(s) |
||||||
A |
44 |
88 |
1010 |
long dash— |
G |
22 |
33 |
44 |
C, E |
||||||
B |
22 |
99 |
2424 |
A |
H |
22 |
22 |
22 |
F |
||||||
C |
99 |
1212 |
1616 |
A |
I |
77 |
77 |
77 |
F |
||||||
D |
44 |
66 |
99 |
A |
J |
44 |
77 |
1212 |
D, G, H |
||||||
E |
11 |
22 |
44 |
B |
K |
11 |
11 |
44 |
I, J |
||||||
F |
55 |
88 |
2121 |
C, E |
a) To find the expected activity time, the beta distribution weights the three time estimates as follows.
Expected Time equals StartFraction left parenthesis a plus 4 m plus b right parenthesis Over 6 EndFractionExpected Time=(a+4m+b)6
Calculate the expected (estimated) time for activity C.
Expected Time =
12.1712.17
weeks (Round your response to two decimal places.)
b) To compute the variance of activity completion time, use the following formula.
Variance equals left parenthesis StartFraction left parenthesis b minus a right parenthesis Over 6 EndFraction right parenthesis squaredVariance=(b?a)62
Calculate the variance for activity C.
Variance =
11
weeks (Round your response to two decimal places.)
Consider the AON network for the project.
font size increased by 1 Upper DD
font size increased by 1 Upper FF
font size increased by 1 Upper GG
font size increased by 1 Upper AA
font size increased by 1 Upper EE
font size increased by 1 Upper CC
font size increased by 1 Upper BB
font size increased by 1 Upper HH
font size increased by 1 Upper II
font size increased by 1 Upper KK
font size increased by 1 Upper JJ
x y graph
c) The length of the path
Upper A minus Upper B minus Upper E minus Upper F minus Upper H minus Upper J minus Upper KA ? B ? E ? F ? H ? J ? K
is
40.6740.67
weeks. (Round your response to two decimal places.)
The length of the path
Upper A minus Upper B minus Upper E minus Upper F minus Upper I minus Upper KA ? B ? E ? F ? I ? K
is
38.3438.34
weeks. (Round your response to two decimal places.)
The length of the path
Upper A minus Upper B minus Upper E minus Upper G minus Upper J minus Upper KA ? B ? E ? G ? J ? K
is
nothing
weeks. (Round your response to two decimal places.)
(a)
Expected activity time for 'C' = (a + 4m + b)/6 = (9+4*12+16)/6 = 12.167 weeks
(b)
Variance of activity time for 'C' = (b - a)2/36 = ((16 - 9)^2)/36 = 1.36
(c)
Activity | a | m | b | te=(a+4m+b)/6 |
A | 4 | 8 | 10 | 7.67 |
B | 2 | 9 | 24 | 10.33 |
E | 1 | 2 | 4 | 2.17 |
F | 5 | 8 | 21 | 9.67 |
H | 2 | 2 | 2 | 2.00 |
J | 4 | 7 | 12 | 7.33 |
K | 1 | 1 | 4 | 1.50 |
Total | 40.67 |
(d)
Activity | a | m | b | te=(a+4m+b)/6 |
A | 4 | 8 | 10 | 7.67 |
B | 2 | 9 | 24 | 10.33 |
E | 1 | 2 | 4 | 2.17 |
F | 5 | 8 | 21 | 9.67 |
I | 7 | 7 | 7 | 7.00 |
K | 1 | 1 | 4 | 1.50 |
Total | 38.33 |
(e)
Activity | a | m | b | te=(a+4m+b)/6 |
A | 4 | 8 | 10 | 7.67 |
B | 2 | 9 | 24 | 10.33 |
E | 1 | 2 | 4 | 2.17 |
G | 2 | 3 | 4 | 3.00 |
J | 4 | 7 | 12 | 7.33 |
K | 1 | 1 | 4 | 1.50 |
Total | 32.00 |
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