Question

The albumin is 4.5g/dL. The avg concentration at steady state is 9mg/dL when the dose is 500mg daily. The dose is raised to 550 mg daily and the avg steady state concentration is 11.5mcg/ml. What is the dose needed to have a steady state concentration of 15mg/dL?

Answer 1

Albumin -4.5g/dL

9mg/dL - avg cncentration 500mg/dL

11.5 mcg/ml - 550 mg/dL

1 mcg/ml = 0.1 mg/dL

so 11.5 mcg/ml = 1.15 mg/dL

1.15mg/dL - avg concentration 550

If dose increases ,then avg concentration decreases

so for inrease dose 50 = decrease avg concentration by 7.5 mg/dL (11.5-9)

Then for avg conc: 1mg/dL = 50/7.5 = 6.7

Given info 9 mg/dL = 500mg/dL avg conc:

so 9+6 mg/dL. = 500- ( 6*6.7)

15 mg/dL. = 500 - 40.2

= 459.8

15 mg/dL - 459.8 mg/dL avg concentration