The dose of a drug is 120 mg/kg/d, infused over 24 hours. What would be the infusion rate, in milliliters per hour, of a 2.5% (w/v) solution of the drug if administered to a patient weighing 176 lb? Round your final answer to the nearest tenth.
Solution:-
Given,
dose of a drug : 120 mg/kg/d, infused over 24 hours.
So, infusion time = 24 hr
patient weight= 176 lb
Now, 1 lb = 0.454 Kg
Or, 176 lb = 0.454 × 176 Kg
=79.90 Kg
Hence, patient's weight (kg) = 79.90 kg
Overall dose for the patient = dose × weight of patient
= 120 mg/Kg/day × 79.90 kg
= 9588 mg/day
= 9.588 g/day
Now, concentration of drug = 2.5 % (w/v)
It means 2.5 g of drug present in 100 ml solution.
Using unitary method:-
2 .5 g of drug present in 100 ml solution
1 g of drug present in =100/2.5 ml solution
9.588 g of drug present in = (100/2.5) × 9.588 ml solution
= 383.52 ml solution
Now, volume of solution = 283.52 ml
Infusion rate (ml/hr) = volume of solution in ml/ infusion time in hr
= 383.52 ml/24 hr
= 15.98 ml/hr
= 16.0 ml/hr [ rounded to nearest tenth]
Therefore, infusion rate = 16.0 ml/hr
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