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Set up a formula (in grams) for 5 pound (avoir.) glycerogelatin containing 10 parts by weight...

Set up a formula (in grams) for 5 pound (avoir.) glycerogelatin containing 10 parts by weight of zinc oxide, 15 parts by weight of gelatin, 40 parts by weight of glycerine, and 35 parts by weight of water.

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Answer #1

The weight of glycerogelatin = 5 pound

1 pound = 453.5 gm

5 pound = 5 x 453.5 = 2267.9 gm

Let take the part by weight of glycerogelatin be x , then

10 parts by weight of zinc oxide = 10x

15 parts by weight of gelatin = 15x

40 parts by weight of glycerine = 40x

35 parts by weight of water = 35x

The sum of total parts by weight = 2267.9gm

S0, 10x + 15x + 40x + 35x = 2267.9

100x = 2267.9

x = 22.6

S0, 10 part by weight of zinc oxide = 10 x 22.6 = 226 gm

15 part by weight of gelatin = 15 x 22.6 = 339 gm

40 part by weight of glycerine = 40 x 22.6 = 904 gm

35 part by weight of water = 35 x 22.6 = 791 gm

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