Question 1
a) The recommended daily dosage of pseudoephedrine hydrochloride for a child is 0.05 g/kg in three divided doses. You have a 15% w/v solution of pseudoephedrine hydrochloride. How many mL of this cold remedy should a 16 kg child be given per dose?
b) Calculate the molarity (M) of a 10% aqueous solution of MgCl2 (molecular weight: 94.
c) You receive a script for Vitamin A solution 3500 units per day. There is a commercially available product containing 3000 units/g. How many drops would you advise the patient to give when the dropper delivers a volume of 2 mL in 25 drops? (Vitamin A product wt/mL 0.9 g)
d) You received a prescription for Codeine linctus 5 mg/mL 100 mL. The market product is currently unavailable so you will have to extemporaneously prepare this. Using the following formula taken from APF 19, work out the amounts to make 100 mL.
Codeine Linctus APF 19 Formula:
Codeine phosphate 25 mg
Purified water 0.5 mL
Glycerol 1 mL
Methyl hydroxybenzoate solution 0.05 mL
Syrup to 5 mL
*Please show all working
Que1. Given , recommended dose for child is 0.5 g /kg per day
Available solution is 15%(w/v),child weight is 16kg
Dose for the child is
If, 0.5g = 1kg
16kg = X g
X= 16×0.5= 8 g
X= 8g /day
Devided in 3 doses in a day so per dose= 8÷ 3
= 2.6666 g per dose
So, one dose is 2.666g
Given, 15% solution means 15g of medication in 100 ml volume of Normal saline or solvent.
If, 15g= 100ml
2.666g = Y ml
Y= (2.666÷15)×100= 17.7733 ml
Y= 17.77ml approx 17.8 ml
So, 17.8ml needed per dose for child.
Que2.Given ,10% of mgCl2 means 10grams of magnesium chloride in 100ml of solvent or normal saline.
Given molar mass=94
By formula
n( no. Of moles)= mass (in grams )÷ M (molar mass)
= 10g× 94= 940 moles
n = 940moles
If 940moles of solute in 100ml solvent
100ml = 940moles
1000ml =Xmoles
X= (1000÷100)× 940 = 9400moles
X= 9400moles in 1L
So, Molarity = number of moles of solute÷ volume (inL)
M=9400moles ÷1 L
M= 9400
9400M
Que3. Given, on script 3500 unit
Available = 3000unit/gram
Available = 0.9g/ml
2ml = 25DROPS
if , 1gram =3000unit
Xgram= 3500unit
X= 3500÷3000= 1.166gram
X= 1.166 grams.
Now if, 0.9g=1ml
1.166g = Yml
Y= 1.166÷0.9 =1.2962 ml
Y= 1.2962ml
If,2ml = 25drops
1.2962ml= Zdrops
Z= (1.2962÷2)× 25= 16.2025 drops
Z= 16.2025 or approx 16 drops
Z=16 drops
16 drops in 1.2962ml needed to administer
Que D. As extemporaneous preparation is for a specific ailment.here its for codein phosphate.so amount of codein phosphate is 25mg in 5ml syrup .
If,25mg of codein phosphate is there in 5ml
25mg = 5ml
100ml = X mg
, X=(100÷5)× 25
X= 500mg
So we will give the patient 100ml With 500 dose of codein phosphate.
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