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What is the osmolarity/L of a solution containing 5% dextrose (MW = 180) and 0.45% sodium...

What is the osmolarity/L of a solution containing 5% dextrose (MW = 180) and 0.45% sodium chloride (MW = 58.5)? Round final answer to nearest whole number.

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Answer:

5% dextrose =5g/100ml =50g/1000ml

Thus, mass in garm of 5% dextrose in 1L =50g

molecular weight =180

number of particles =1 ( only dextrose)

  

0.45% sodium chloride=0.45g/100ml = 4.5g/1000ml

Thus, mass in gram of 0.45% sodium chloride = 4.5g

molecular weight = 58.5

number of particles = 2( sodium and chloride)

  

  

Osmolarity/L of total solution = Osmolarity/L of 5% dextrose + osmolarity/L of .45% sodium chlioride

= 277.77 + 153.84

=431.6, rounding off 432

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