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8. A woman is heterozygous for Huntington’s Chorea. A man is healthy. What will be the...

8. A woman is heterozygous for Huntington’s Chorea. A man is healthy. What will be the probable phenotypes of their children and the probability of each phenotype occurring? Pick one.

a. 100% of the children will probably be healthy.

b. 100% of the children will probably have the disease.

c. 50% of the children will probably be healthy, and 50% will have the disease .

d. 75% of the children will probably be healthy, and 25% will have the disease.

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Answer #1

Answer-8:

(√) c. 50% of the children will probably be healthy, and 50% will have the disease.

Explanation: 1. Above mentioned option is correct because if any one of the parent is having heterozygous for Huntington's Chorea in that case the chances of their offspring to be healthy and with disease will be 50-50 because it is an autosomal cardinal condition that means a single abnormal gene can lead to the disease phenotype in an individual.

2. As mother is affected by heterozygous disease, there are 50% chances that gene will cause disease in the offspring and 50% chances that it will not cause disease in the offspring.

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