Question

A medication order for a patient weighing 170 lbs calls for 0.25 mg/kg of amphotericin B to be added to 250 mL of 5% dextrose injection. The pharmacy has a vial of amphotericin B available in the concentration of 50 mg/10 mL. How many milliliters of amphotericin B should be added to the dextrose injection? (Tip: you should know the appropriate rounding based on the instrument you will use to measure)

Answer #1

Solution:

Weight : 170 lbs = 77.1 kg

Given, 0.25 mg/kg of amphoteric b to be added to 250 ml of 5% dextrose solution.

For 1kg : 0.25 mg amphotericin needed

Thus for 77 kg:? Amphotericin needed

=77.1/0.25

=19.275mg

Thus total of 19.275 mg of amphotericin b is needed for this patient.

Available Amphotericin b vial= 50mg/10ml

So, For 50 mg : 10 ml is required

Thus for 19.275:? Required

=19.275×10/50

=4ml

Thus 4ml of Amphotericin B should be added to dextrose injection.

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