Question

The pharmacist needs to partially combine the contents of two bags of medication into a new bag. Bag A contains 15 mg of medication in a 100 ml 0.9%Nacl. Bag B contains 190 mg of medication in 1000ml. She combines ½ of Bag B with all of the contents of Bag A; and now as a new bag … Bag C. If the patient was to receive 80% of the fluid from bag C, how many mg would the patient receive?

Please show work.

Answer 1

Given data

Bag A contains 15 mg of medication in a 100 mL

   Bag B contains 190 mg of medication in 1000mL (half (1/2) content of bag B is 95 mg in 500 mL)

New bag, bag C contains all of the contents of bag A + half (1/2) of bag B

So, bag C contains 15 mg in a 100 mL (content of bag A) + 95 mg in 500 mL (1/2 content of bag B)

There for bag C contains 110 mg in 600 mL (15 mg+95 mg and 100 mL+500 mL)

Now patient is receiving 80% of fluid from bag C

80% of fluid of bag C = (Total fluid/100) x 80 (100 = %)

= (600 mL /100) x 80 = 480 mL

Patient is receiving 80% of fluid from bag C means patient is receiving 480 mL of fluid from bag C

mg of medicine in 80% (480 ml)of fluid = (480 mL x 110 mg)/600 mL

= 88 mg

The answer is

Patient receives 88 mg of medicine from 80% (480 ml)of fluid from bag C