Question

CJ is a 72 years old male patient weighing 234 lb and 6’3” tall. He is moderately stressed due to his emphysema (stress factor = 1.5) but remains ambulatory (activity factor = 1.3). The protein requirement of CJ was determined to be 1.5 g/kg/day. Currently, he is receiving 30% of his daily caloric requirement from lipids.

Calculate the amount of dextrose needed to supply the parenteral nutrition carbohydrate requirement for CJ.

Answer 1

Age -72years

Weight - 234lb = 105.3kg

Height - 6'3" = 190.5cm

BMR = 10W + 6.25H - 5A + 5

= 10×105.3+ 6.25×190.5 -5×72+ 5

= 1053+ 1190.6- 365

= 1878.6kcal ( total )

Protein requirement -1.5/kg/day

= 1.5× 105.3kg /day = 157.9kcal

Fat = 30% of 1878.6 = 563.5kcal

Calories of carbohydrates = 1878.6kcal - ( 157.9+ 563.5kcal)

= 1157.2 kcal

I gm of carbohydrates provides 4kcal

= 1157.2 kcal /4 kcal = 289.3gm of dextrose

#. Divide dextrose grams by remaining fluid needs and multiply by 100 to determine dextrose concentration.

Fluid need of the patient is 1500ml + 20ml /kg ( each kg more than 20kg ) = 2540

= 289.3gm/2540 × 100= 11.3% dextrose