Calculate the number of grams of dextrose in the following solution: 150 mL D20 1/4 NS. Do not round; include the unit with your answer as an abbreviation.
Given,
150 ml D20 1/4 NS(normal saline)
Now, D20 1/4 NS means 20% dextrose in 100 ml solution
(mass/volume percent), that is 20 gram dextrose present in 100 ml
ns solution.
Now, using unitary method:-
100 ml 1/4 NS solution contain 20 grams dextrose
1 ml 1/4 NS solution contain =20/100 grams dextrose
150 ml 1/4 NS solution contain =(20/100)×150 grams dextrose
=30 grams dextrose.
Therefore, 30 grams of dextrose present in the 150 ml D20 1/4 NS.
note:-
Normal saline contain 0.9% W/V NaCl
Half(1/2) normal saline contain 0.45% W/V NaCl
Quarter (1/4 NS) normal saline contain 0.22% W/V NaCl
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