Question

From the following formula for an oral electrolyte solution, calculate the amount of chloride (in mEq) required to prepare 1,684 mL of the solution.

Sodium 45 mEq
Potassium 20 mEq
Chloride 28 mEq
Citrate 30 mEq
Dextrose 25 g
Water ad 238 mL

Answer 1

Question:

From the following formula for an oral electrolyte solution, calculate the amount of chloride (in mEq) required to prepare 1,684 mL of the solution.

Sodium 45 mEq
Potassium 20 mEq
Chloride 28 mEq
Citrate 30 mEq
Dextrose 25 g

Water ad 238 mL

Answer:

From the above used formula,The amount of chloride used for making 238 mL of solution is 28mEq.

So, let us find out 100mL of solution contains how much the chloride?

The formula is = The Amount of solvent / Total Solution * Desired amount of solution.

The amount of solvent is 28mEq chloride

Total amount of solution available is 238 mL

Desired amount of solution is 100mL.

So if the formula is applied 28/238*100 = 11.76mEq

100mL of solution contains 11.76mEq chloride.

Inorder to prepare 1684 mL apply the same formula.

The amount of Solvent in 100mL is 11.76.

Total amount of solution is100mL

Desired amount of solution is 1684mL

The formula is = The Amount of solvent / Total Solution * Desired amount of solution.

So to prepare 1684 mL of Solution = 11.76/100*1684 = 198mEq

So the answer is 198mEq chloride is required to prepare 1684 mL of solution.