A resultant force of 32 000 N acts on a 225 cm2 area at an angle
of 44° with respect to a normal to the area due to pressure and
friction. The pressure on the area is nearest (in kPa):
a. 23.02
b. 988.0
c. 1023
d. 22.23
e. 1422
Given resultant force acts at angle 44 degrees to normal
Resultant force = Fr
The normal force acting on the area is =Fn
Pressure acting normal to the force is given by
Area (A)= 225 cm^2
Area = 225 * 10^(-4) mt^2

Option C is correct
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