A Carnot engine extracts 100 kJ of heat from an 800°C reservoir and rejects to the surroundings at 20°C. Calculate the entropy change (a) of the reservoir and (b) of the surroundings.
Dear student,
Inorder to calculate entropy change of hot reservoir and environment surrounding. We need to know the heat extrated(lost from hot reservoir) and heat rejected (head added to cold reservoir) .
This can be calculated using second law of thermodynamics as shown below.
From the above we see that
Change in entropy of hot reservoir + Change in entropy of cold reservoir = 0
Therefore entropy change of carnot cycle is zero.
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