Air is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8-cm-outer-diameter and 0.8-m-long tubes inside which the refrigerant is evaporating at −20°C. Air approaches the tube bank in the normal direction at 0°C and 1 atm with a mean velocity of 9 m/s. The tubes are arranged in-line with longitudinal and transverse pitches of SL = ST = 1.5 cm. There are 25 rows in the flow direction with 15 tubes in each row. Assume the mean temperature as −5°C and the properties of air at this temperature and 1 atm are (Table A-15) k = 0.02326 W/m⋅K, cp = 1.006 kJ/kg⋅K, ρ = 1.317 kg/m3, Pr = 0.7375, μ = 1.705 × 10−5 kg/m⋅s, and Prs = Pr@Ts = –20°C = 0.7408. Also, the density of air at the inlet temperature of 0°C (for use in the mass flow rate calculation at the inlet) is ρi = 1.292 kg/m3.
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Determine the refrigeration capacity of this system.
The refrigeration capacity of the system is W.
Determine the pressure drop across the tube bank. (Round off SLD/SLD value to the nearest whole number.)
The pressure drop across the tube bank is Pa.
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