Question

A water jet with a velocity 3.3 V strikes a moving plate of a trolley moving towards at a velocity of 2 V, .If the density of the water is r, and the cross sectional area of the water jet is A, the force acting on the moving plate is given by the equation:

Select one:

=(3.3+2)*rAV^2

=(3.3-2) rAV

=(3.3+2)^2*rAV^2

=(3.3-2)*rAV^2

Answer 1

Solution:

Let,

3.3 V = Velocity of the jet

2V = Velocity of the plate of the trolley.

Velocity of the jet relative to the plate = (3.3V + 2V)

We may consider as though the plate is at rest and that the jet is moving with a velocity (3.3V+2V) relative to the plate.

∴ Force exerted by the jet on the plate P

= ρA *(3.3 V+2V)² Newton

= ρAV²(3.3+2)²

Force F is given by F= ρAV²(3.3+2)²

^{Correct Ans is Number 3}

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