A refrigeration system using refrigerant 22 is to have a refrigerating capacity of 80kw. The cycle is a standard vaporcompression cycle in which the evaporating temperature is 9 C and the condensing temperature is 42 C, sketch the cycle on pressure enthalpy coordinates. Calculate

As nothing is stated about superheating and subcooling, we will assume there is none. Using the information from the data provided, we can draw the process diagram as follows
Here 12 is the evaporator, 23 is a compressor, 34 is condenser and 41 is throttling valve
From a pH chart for R22, we get the enthalpy values. Please note that I am not allowed to post an actual pH chart because of legal reasons.
Point  Enthalpy 
1  105 
2  240 
3  280 
4  105 
Thus refrigeration effect per unit mass flow rate of refrigerant is h2h1 = 240  105 = 135 kJ/kg
It is given that the refrigeration effect is 80 kW. Thus the mass flow rate of refrigerant m is 80/135 = 0.592 kg/s
The specific volume at the compressor entrance (point 2) is obtained from the chart as 0.06 m3/kg
So volume flow rate at entrance of compressor is 0.06*0.592 = 0.03552 m3/kkg
The power input to compressor is the product of mass flow rate and change in enthalpy per unit mass refrigerant across the compressor. Hence compressor power is m*(h3h2) = 0.592 (280240) = 23.68 kW
From the pH chart, at point 1, we obtain the dryness fraction as close to 0.34. This denotes the amount of vapour in the flow of the refrigerant.
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