Rotate around the ?-axis the region ? = {(?, ?) ∈ ? 2 : sin ? < ? < π − ?, 0 < ? < π} to obtain the solid Ω. Find its volume and center of mass.
SOLUTION:
The given expression is :
? = {(?, ?) ∈ ? 2 : sin ? < ? < π − ?, 0 < ? < π}
The region is rotated around Z axis so that occupied region will be Symmetric about X-Z plane.
Now,
1) Find Volume of that Region :
the area of small segment assumed in the region as shown in the figure is,dA
that is, , so when this segment is being rotated around Z axis, it will create a ring, which Volume (dV) is,
Now, the full volume of the region can be calculated by integrating small volume withing given range,
------------------------- (ii)
so,
2) Find the centre of mass of the given region:
The region is rotated around Z-axis so that occupied region will be Symmetric about X-Z plane. hence the centre of mass will lie in the x-z plane only.
The X - coordinate of Centre of mass is:-
so,
Similarly for
so,
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