If we are using a 3-4-5 polynomial for a RDFD cam design where we rise to h = 1in in 45deg (beta1), dwell for 150deg (beta2), fall back to 0in in 90 deg (beta3) and dwell for the remainder. What is the position (s) when theta = 225 deg. Hint: If theta = 225 deg then we are 30deg into the fall or 225-beta1-beta2 = 30 so in your fall equations the fraction theta/beta3 = 30/90 or 0.3333. Note: This is a little harder since you are not used to focussing on the fall values. Round your answer to the nearest tenth.
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