Question

A partly-filled propane tank is positioned on a weigh scale that indicates its initial mass is...

A partly-filled propane tank is positioned on a weigh scale that indicates its initial mass is 10 kg. The tank is then connected to a supply line through which propane flows into the tank at 10 grams/second. What will be the mass of the tank and its contents if it filled at this rate for 15 minutes?

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Answer #2

Here the initial mass of tank and contents =10kg

Now its filled with a rate of 10 grams/second.

15 minutes = 15*60 = 900 seconds

So In 15 minute newly added Propane = Fill rate * seconds in 15 minutes

= 10 * 900

= 9000 grams

= 9 kg ( because 1 kg = 1000 grams )

So after 15 minute mass of tank and content = Initial mass + Mass of fillled in 15 minutes

= 10 + 9

= 19 kg. <<<<<<<<< ANSWER

If you find any query please comment below I will guide you surely. THANK YOU.

answered by: anonymous
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