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an opaque surface with an emissivity of .85 and an absorptivity of .45 is at 324...

an opaque surface with an emissivity of .85 and an absorptivity of .45 is at 324 kelvin. the blackbody temperature of its large surroundings is 622 kelvin. estimate the radiosity of this surface, J=E+rhoG

Engineering   Mechanical-Engineering   
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Answer #1

Radiosity is defined as the total radiation leaving a surface.

It includes all reflected radiations and the radiation emmited by the surface due to its own temperature also.

see below complete solution.

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