Question

find the equation of a tangent line(s) to the curve with slope 5

f(x)=x^3 + 3x^2 - 4x - 12

f'(x)= 3x^2 +6x - 4

Answer #1

Find fhe equation of the tangent lines with slope of 5
a) f(x)= x^3 + 3x^2 - 4x -12
b) g(x)= 3x^2 + 6x - 4

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