Question

1. Test the series below for convergence using the Root Test. ∞∑n=1 (4n/10n+1)^n The limit of...

1. Test the series below for convergence using the Root Test.
∞∑n=1 (4n/10n+1)^n
The limit of the root test simplifies to lim n→∞ |f(n)| where
f(n)=
The limit is:    
Based on this, the series

  • Diverges
  • Converges

2. We want to use the Alternating Series Test to determine if the series:

∞∑k=4 (−1)^k+2 k^2/√k^5+3

converges or diverges.
We can conclude that:

  • The Alternating Series Test does not apply because the terms of the series do not alternate.
  • The Alternating Series Test does not apply because the absolute value of the terms do not approach 0, and the series diverges for the same reason.
  • The series converges by the Alternating Series Test.
  • The series diverges by the Alternating Series Test.
  • The Alternating Series Test does not apply because the absolute value of the terms are not decreasing.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. Test the series below for convergence using the Root Test. ∞∑n=1 (2n^2 / 9n+3)^n The...
1. Test the series below for convergence using the Root Test. ∞∑n=1 (2n^2 / 9n+3)^n The limit of the root test simplifies to limn→∞|f(n)|limn→∞|f(n)| where f(n)= 2. Test the series below for convergence using the Root Test. ∞∑n=1 (4n+4 / 5n+3)^n The limit of the root test simplifies to limn→∞|f(n)| where f(n)=   The limit is:
1. To test the series ∞∑k=1 1/5√k^3 for convergence, you can use the P-test. (You could...
1. To test the series ∞∑k=1 1/5√k^3 for convergence, you can use the P-test. (You could also use the Integral Test, as is the case with all series of this type.) According to the P-test: ∞∑k=1 1/5√k^3 converges the P-test does not apply to ∞∑k=1 1/5√k^3 ∞∑k=1 1/5√k^3 diverges Now compute s4, the partial sum consisting of the first 4 terms of ∞∑k=1 1 /5√k^3: s4= 2. Test the series below for convergence using the Ratio Test. ∞∑n=1 n^5 /1.2^n...
1. To test this series for convergence ∞∑n=1 n /√n^3+1 You could use the Limit Comparison...
1. To test this series for convergence ∞∑n=1 n /√n^3+1 You could use the Limit Comparison Test, comparing it to the series ∞∑n=1 1 /n^p where p= 2. Test the series below for convergence using the Ratio Test. ∞∑n=1 n^5/0.5^n The limit of the ratio test simplifies to lim n→∞|f(n)| where f(n)=    The limit is:
Apply the Root Test to determine convergence or divergence, or state that the Root Test is...
Apply the Root Test to determine convergence or divergence, or state that the Root Test is inconclusive. from n=1 to infinity (3n-1/4n+3)^(2n) Calculate lim n→∞ n cube root of the absolute value of an What can you say about the series using the Root Test? Determine whether the series is absolutely convergent, conditionally convergent, or divergent.
Test the series for convergence or divergence. ∞ (−1)n 8n − 5 9n + 5 n...
Test the series for convergence or divergence. ∞ (−1)n 8n − 5 9n + 5 n = 1 Step 1 To decide whether ∞ (−1)n 8n − 5 9n + 5 n = 1 converges, we must find lim n → ∞ 8n − 5 9n + 5 . The highest power of n in the fraction is 1    1 . Step 2 Dividing numerator and denominator by n gives us lim n → ∞ 8n − 5 9n +...
Consider the series ∑n=1 ∞ an where an=(5n+5)^(9n+1)/ 12^n In this problem you must attempt to...
Consider the series ∑n=1 ∞ an where an=(5n+5)^(9n+1)/ 12^n In this problem you must attempt to use the Ratio Test to decide whether the series converges. Compute L= lim n→∞ ∣∣∣an+1/an∣∣ Enter the numerical value of the limit L if it converges, INF if the limit for L diverges to infinity, MINF if it diverges to negative infinity, or DIV if it diverges but not to infinity or negative infinity. L= Which of the following statements is true? A. The...
Test for absolute or conditional convergence (infinity, n=1) ((-1)^n(4n))/(n^3+1)
Test for absolute or conditional convergence (infinity, n=1) ((-1)^n(4n))/(n^3+1)
Test the series for convergence using the Alternating Series Test: X∞ m=2 (−1)^m/ (m 2^m). If...
Test the series for convergence using the Alternating Series Test: X∞ m=2 (−1)^m/ (m 2^m). If convergent, determine whether this series converges absolutely or conditionally
Determine if the series, k = 1 to ∞ , with terms (-1)k ((k - 1)/(k3/2...
Determine if the series, k = 1 to ∞ , with terms (-1)k ((k - 1)/(k3/2 + 1))2 converges absolutely, converges conditionally, or diverges. Tell which convergence test you are using.
The power series  ∑ an is defined as a1 = 1/2 and an+1=((4n-1)/(3n+2)) an . Determine if...
The power series  ∑ an is defined as a1 = 1/2 and an+1=((4n-1)/(3n+2)) an . Determine if the series converges or diverges. Write the test step by step.