Question

Find the limit if it exists or show that the limit does not exist.

lim (x,y) to (0,0). y^2 sin^2x/ x^4+y^4

Answer #1

Determine each limit or explain why the limit does not
exist.
(a) lim(x,y)→(5,4) : (x − y − 1)/(√(x − y) − 1)
(b) lim(x,y)→(0,1) : (sin(x^(2) + y − 1))/(5y + x^(2) − 5)
(c) lim(x,y)→(3,2) : (4x + y)/(2x − 6)

find the limit, if it exists
Lim (x,y)=(0,0) (xy^4)/((x^2)+(y^8))

Consider the function given byf(x, y)
=((y^2−2^x)/(2x^2+y^2))^3.Show that lim(x,y)→(0,0)f(x, y)does not
exist by computing the limit along the positivex-axis and the
positivey-axis.

Find the limit, if it exists. (If an answer does not exist,
enter DNE.)
lim (x, y)→(0, 0)
x2 + y2/square root (x2 +
y2+ 25)-5

f(x,y) = (x^4-y^2) / (x^4 + y^2). show the following limit does
not exist, and explain why lim (x,y)->(0,0) f(x,y)

Calculate each limit below, if it exists. If a limit does not
exist, explain why. Show all work.
\lim _{x\to 3}\left(\frac{x-3}{\sqrt{2x+3}-\sqrt{3x}}\right)
\lim _{x\to -\infty }\left(\frac{\sqrt{x^2+3x}}{3x+1}\right)

Find the limits, if they exist, or type DNE for any
which do not exist.
lim(x,y)→(0,0)5x^2/2x^2+y^2
1) Along the xx-axis:
2) Along the yy-axis:
3) Along the line y=mxy=mx :
4) The limit is:

Evaluate the limit. (If an answer does not exist, enter
DNE.)
lim x→0+ (9x)sin(4x)

hi guys , using this definition for limits in higher dimensions
:
lim (x,y)→(a,b) f(x, y) = L
if 1. ∃r > 0 s.th. f(x, y) is defined when 0 < || (x, y) −
(a, b) || < r
and 2. given ε > 0 we can find δ > 0 s.th. 0 < || (x,
y) − (a, b) || < δ =⇒ | f(x, y) − L | < ε
how do i show that this is...

MY NOTES
Determine the limit of the trigonometric function (if it
exists). (If an answer does not exist, enter DNE.)
lim x→1/2 4x2 tan
πx

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago

asked 4 hours ago

asked 4 hours ago

asked 4 hours ago

asked 4 hours ago

asked 5 hours ago

asked 5 hours ago

asked 5 hours ago