y^2-3y=4x
sorry the problem is y squared minus 3y is equal to 4x and we are to solve for "y"
That is the problem we were given.i wish I could send you a screenshot, but it is not working
As stated in question, we were given only one equation.
But there are two variables named x and y.
In this type of situtation, there will be infinite number of solutions. for every value of x we have, there will be a value exist for y.
lets give x=1, we have the equation now as y2-3y-4 = 0
which can be represented as y2-4y+y-4 = 0
further, y(y-4)-1(y-4) = 0
which gives, (y-1)(y-4)=0
for x=1, we have y=1 or y=4
So, similar to this there will be infinite set of solutions.
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